MathML Plugin example
Following code :
Suppose {{{`ax^2+bx+c=0`}}} and {{{`a!=0`}}}. We first divide by {{{`a` to get {{{`x^2+b/ax+c/a=0`}}}.
Then we complete the square and obtain {{{`x^2+b/ax+(b/(2a))^2-(b/(2a))^2+c/a=0`}}}.
The first three terms factor to give {{{`(x+b/(2a))^2=(b^2)/(4a^2)-c/a`}}}.
Now we take square roots on both sides and get {{{`x+b/(2a)=+-sqrt((b^2)/(4a^2)-c/a)`}}}.
Finally we move the {{{`b/(2a)`}}} to the right and simplify to get
the two solutions: {{{`x_(1,2)=(-b+-sqrt(b^2-4ac))/(2a)`}}}
give :
Suppose `ax^2+bx+c=0` and `a!=0`. We first divide by `a` to get `x^2+b/ax+c/a=0`.
Then we complete the square and obtain `x^2+b/ax+(b/(2a))^2-(b/(2a))^2+c/a=0`. The first three terms factor to give `(x+b/(2a))^2=(b^2)/(4a^2)-c/a`. Now we take square roots on both sides and get `x+b/(2a)=+-sqrt((b^2)/(4a^2)-c/a)`.
Finally we move the `b/(2a)` to the right and simplify to get the two solutions: `x_(1,2)=(-b+-sqrt(b^2-4ac))/(2a)`